the magnitude of AxB = AB sin (theta)What is the magnitude of AxB if A and B are perpendicular?
I read it , but don't get anything about this problem.Did you not read the next paragraph? It explicitly deals with this.
thankkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkks u vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv muchhhhhhhhhhFrom a given element of current you have a magnetic field that is at an angle to the axis of the loop. But the element on the other side of the loop generates a magnetic field that is at the same angle but in the opposite direction. The components in the direction of the axis add while the components perpendicular to the axis cancel. So you figure component in the direction of the axis using the magnitude and the angle and then integrate it around the loop.
I have read that paragraph again and have understood well, thanxYou're welcome. Glad you got it. Now take a moment to read that that paragraph again and be sure that you understand why it is telling you the same thing that I did, only requiring that you fill in a couple small blanks. Those blanks are things that you should be very comfortable with by this point in your education. This is a trend that will continue -- the size of the blanks will get bigger and deeper and require you to draw upon more and more of your background. So you need to work on being able to do that now, while the blanks are relatively small and shallow.
by Jake Hertz
by Duane Benson