Low Shutoff Voltage Regulator

Discussion in 'General Electronics Chat' started by axeman22, Jun 8, 2009.

1. axeman22 Thread Starter Active Member

Jun 8, 2009
53
0
Hi All,

I'm familiar with using the 7805 reg to some degree, like the one referenced here http://www.datasheetcatalog.org/datasheets/150/44435_DS.pdf

I'm hoping someone could explain..:

1. Dropout Voltage.. I think I get this, if so these would be correct.. no ..? - for the 7805 5V Reg
Vin/Vout
10 / 5
8 / 5
7 / 5
6 / 5
5 / 5
4 / 4
3 / 3
2 / 2 - Dropout Voltage..
1.9 / 0
1.5 / 0
1 / 0

2. What happens to the excess voltage.. is it just dissipated in heat?

3. Slightly outside the scope of the question but what would I use for a situation where my Vin will start at 10V and slowly decline to say 3volts but I want to have a 5V regulated(and no less than 5V) for as long as I can.. i.e. a dropout at 5V.
Curve like this..;
Vin / Vout
10 / 5
8 / 5
6 / 5
5 / 5 - dropout here
4.8 / 0 - below droput
4 / 0
3 / 0

feeling like this is a long winded question.. but thanks in advance, no doubt a simple answer!

2. eblc1388 Senior Member

Nov 28, 2008
1,542
102
Your interpretations of the dropout voltage is incorrect.

A voltage regulator is meant to regulate its output voltage to a certain fixed voltage level, with changing input voltage level.

Dropout voltage is the extra voltage that is necessary *above* the output voltage such that the regulator can do its job, i.e. regulating.

For 7805 under load, that voltage is typically about 2 to 3V more than the output voltage, so it meant 7V or more input voltage.

If the input voltage falls below 7V, the regulator cannot regulate and so the output voltage falls too, along with the fall of the input voltage. However, it does not drop to zero volt suddenly.

If this 2V dropout voltage in 7805 is too high for your application, then there are "low dropout(LDO)" regulators available that has a very small voltage differential margin between input and output of 0.2V or less. This means the regulator can provide a stable +5V with just 5.2V or more input voltage.

3. axeman22 Thread Starter Active Member

Jun 8, 2009
53
0
thanks..!

any ideas on question 3 ..?

4. gotumal Active Member

Mar 24, 2008
99
0
May be a zener of 5.1V inseries with a base of a transistor?

5. jpanhalt AAC Fanatic!

Jan 18, 2008
5,699
909
You can make a sharp cut-off with another device, as suggested. You might consider using a comparator that turns off the enable pin of your voltage regulator when the supply voltage is too low. A lot of regulators have enable pins.

Or, go to DigiKey and search on voltage regulator >special purpose>voltage regulator/detector

DigiKey carries the Seiko brand. You can set a cut-off voltage such that when the supply falls below that voltage, the output goes to zero.

John