Hello everyone,
I have figured out the amount of current it takes, it functions like this:
= 12/2(1 - e^-4/3.5)
=6( 1 - e^-1.1428)
4.0866 = 6 ( 0.6811)
Cant figure out the seconds because i'm not sure how to find -t of logs:
So setup the second equation we have
5 = 12/2( 1 - e^-t/3.5)
Thanks
I have figured out the amount of current it takes, it functions like this:
= 12/2(1 - e^-4/3.5)
=6( 1 - e^-1.1428)
4.0866 = 6 ( 0.6811)
Cant figure out the seconds because i'm not sure how to find -t of logs:
So setup the second equation we have
5 = 12/2( 1 - e^-t/3.5)
Thanks