Dear sir/madam,

i have made one voltage boost circuit. my input is 3 of 3.7v lithium batteries. they are always connected to the circuit. and the circuit is then connected to another circuit with 555 chip in it.
as long as i off the switch i am fine. but by mistake if i leave the switch on and even though the switch for the lights is off the battery keeps draining slowly. How can i avoid the lithium batteries not drain beyond certain point. like say 3v so 3 x 3v is 9v.
if my lithium batteries over discharge they are not charging back. Please help to solve this small problem.
thank you in advance.

Best Regards,
Imran

 

You need a low voltage cutout. It's hard to say more without a schematic.

 

A boost converter will draw a small current even if it has no load on it. To avoid that you must disconnect the battery from the converter. Some converters have a shutdown pin and if it is shutdown that way it will draw negligible current so that is an alternative way of reducing the current.

 

You need a low voltage cutout. It's hard to say more without a schematic.

Maxim do a variety of off the shelf voltage monitor chips.