Linear circuit KCL help- EASY

Discussion in 'Homework Help' started by caliendo, Mar 26, 2009.

  1. caliendo

    Thread Starter New Member

    Mar 26, 2009
    3
    0
    Hey guys I have a test tomorrow and this is my first time to post here so thanks for the help!

    Heres the question, I just have to find V0 and Vs. Here is the answer sheet to the problem, what I don't understand is why is the node 3V0 and why across that resistor is it 2v0? Thanks for the help guys.!

    [​IMG]
     
    Last edited: Mar 26, 2009
  2. Ratch

    New Member

    Mar 20, 2007
    1,068
    3
    caliendo,

    Sure, it's easy. Vo is 2 volts. 2 volts across a 1k resistor is 2 ma. That same 2 ma goes through the 2k resistor to make 4 volts = 2Vo across it. So 2 volts from Vo plus 4 volts from the 2k resistor makes 6 volts, which is 3 times Vo.

    Ratch
     
  3. caliendo

    Thread Starter New Member

    Mar 26, 2009
    3
    0
    doh! that is easy! thank you so much!
     
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