Limiting/Clamping Circuit (Diodes)

Discussion in 'Homework Help' started by jegues, Apr 21, 2011.

  1. jegues

    Thread Starter Well-Known Member

    Sep 13, 2010
    735
    43
    See figure attached.

    I agree with part a) but in part b) isn't there a mistake?

    v_{A} - v_{B} = I5k

    v_{A} = v_{B} = -I_{1}5k + v_{B}

    Isn't he off by a negative sign on VB?
     
  2. designnut

    Member

    Apr 21, 2011
    33
    1
    The voltage at Vc will only be positive and will be one sixth of the input minus two diode drops.
     
  3. jegues

    Thread Starter Well-Known Member

    Sep 13, 2010
    735
    43
    This doesn't answer my question?
     
  4. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    5,448
    782
    You are right - part (b) solution is incorrect as shown.

    VA=VB-5000*I is the right answer.
     
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