Ok , I am trying to understand some of the characteristic's stuff.
This package of radio shack part 276-142 Infrared Emitter / Detector.
It has Detector__________________________________________
Max voltage and current
Collector to emitter 70 V
Emitter to collector 5V
Collector current 50mA
Total power dissipation 150mW
peak sensitivity wavelength 850nm
spectral bandwidth range: 620 - 980nm
angle of half sensitivity = +-20 degrees
_________________________________________________________
Emitter has
Max current and voltage ratings
Reverse voltage 5V
Continous forward current 150mA
Forward voltage 1.3v typ. 1.7v max
radiant power output 13 - 15mW
Wavelength at peak emission 950nm
________________________________________________________
First , I would think that the forward current * forward voltage = the radiant power output?
But 1.3v * 0.15 A = 195 mW much >>> then 13mW - 15mW.
Is it lossing this much enery in the form of heat?
Wavelength at peak emission how did they calculate the peak emission?
And for the detector
peak sensitivity wavelength 850nm
spectral bandwidth range: 620 - 980nm
angle of half sensitivity = +-20 degrees
what is the angle of half sensitivity for? Does it mean if I put the detector at an angle of more then 20 degrees it would give a less then have strength of the signal?
spectral bandwidth range can I some how build a circuit so it output's any frequency I want with in the 620 - 980nm. If so what controlls this and how did they come up with this range?
And how do you know from these chracteristics what the max transmission can be? Like how far away can I put the detector from the emitter to have it still work.
And must their be a line of sight with infrared or can it pass thru stuff like wall's etc?
Thanks for any clarity on these questions.
This package of radio shack part 276-142 Infrared Emitter / Detector.
It has Detector__________________________________________
Max voltage and current
Collector to emitter 70 V
Emitter to collector 5V
Collector current 50mA
Total power dissipation 150mW
peak sensitivity wavelength 850nm
spectral bandwidth range: 620 - 980nm
angle of half sensitivity = +-20 degrees
_________________________________________________________
Emitter has
Max current and voltage ratings
Reverse voltage 5V
Continous forward current 150mA
Forward voltage 1.3v typ. 1.7v max
radiant power output 13 - 15mW
Wavelength at peak emission 950nm
________________________________________________________
First , I would think that the forward current * forward voltage = the radiant power output?
But 1.3v * 0.15 A = 195 mW much >>> then 13mW - 15mW.
Is it lossing this much enery in the form of heat?
Wavelength at peak emission how did they calculate the peak emission?
And for the detector
peak sensitivity wavelength 850nm
spectral bandwidth range: 620 - 980nm
angle of half sensitivity = +-20 degrees
what is the angle of half sensitivity for? Does it mean if I put the detector at an angle of more then 20 degrees it would give a less then have strength of the signal?
spectral bandwidth range can I some how build a circuit so it output's any frequency I want with in the 620 - 980nm. If so what controlls this and how did they come up with this range?
And how do you know from these chracteristics what the max transmission can be? Like how far away can I put the detector from the emitter to have it still work.
And must their be a line of sight with infrared or can it pass thru stuff like wall's etc?
Thanks for any clarity on these questions.
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