why does an LED I-V curve look exponential? What causes this? How would one compare a measured graph to a theoretical LED I-V curve?
because it's a diode?why does an LED I-V curve look exponential?
So that's what the D stands for in LED. Who knew?because it's a diode?
Precisely. Many components don't have a straight, or linear, I-V characteristic. Physically, as the voltage across a PN junction (a diode) increases, the "depletion region" between the PN junction shrinks, leading to, effectively, lower resistance overall. I like to look at it as though resistance decreases with voltage, so the current increases exponentially with voltage. I'll probably be yelled at for saying that, but it works for me.because it's a diode?
Well, incrementally, I would agree that small signal ac resistance increases as the diode is biased upward on the I-V curve. But re "resistance" in the general sense, I don't think I agree with you.Precisely. Many components don't have a straight, or linear, I-V characteristic. Physically, as the voltage across a PN junction (a diode) increases, the "depletion region" between the PN junction shrinks, leading to, effectively, lower resistance overall. I like to look at it as though resistance decreases with voltage, so the current increases exponentially with voltage. I'll probably be yelled at for saying that, but it works for me.
Of course, I was just saying that you cannot regard diode "resistance" the same as in the general Ohmic sense. It is non-linear, & varies with I-V operating point, as well as temperature. An equation or graph is needed to understand the device fully, as the simple R = V/I relation does not hold.LEDs and diodes are classified as non-ohmic or non-linear, but they still have resistance to a DC current flow and dissipate power as determined by V * I at their operating point. The have a non-linear resistance.
I think you meant "decreases".Well, incrementally, I would agree that small signal ac resistance increases as the diode is biased upward on the I-V curve. But re "resistance" in the general sense, I don't think I agree with you.
Claude
Yes I did mean to say decrease. Sorry if I led anybody astray. As dc bias I-V point increases, incremental resistance decreases.I think you meant "decreases".
They also developed a version called the DEAD. The yield on both of these was said to be fantastic.Of course none of this applies to the DED released by Fairchild Semi about 40 years ago around April 1.
It was brief, but spectacular.But they sure took a lot of current to achieve a reasonable light output.
by Aaron Carman
by Don Wilcher
by Aaron Carman