LC Band Pass Filter Network

Discussion in 'Homework Help' started by Cryptokyo, Sep 25, 2016.

  1. Cryptokyo

    Thread Starter New Member

    Sep 25, 2016
    1
    0
    Hello everyone,

    I have attached the 3 questions I am wrestling with.

    For 10 I used the equation: f_{0}=\frac{1}{2\pi\sqrt{LC}} to obtain f_{0}=50.3kHz

    For 11 I used the equation: R_{D}=\frac{L}{r_{L}C}, with r_{L}=100\Omega to obtain R_{D}=100k\Omega

    For 12 I treated it as if it was a voltage divider so: V_{out}=1\times\frac{100k\Omega}{100k\Omega + 10k\Omega}=0.91V

    I feel as if this is incorrect. Can anyone just give this a quick check over as I am relatively new to AC circuits.
    LC Network.JPG
     
  2. MrAl

    Well-Known Member

    Jun 17, 2014
    2,418
    488
    Hi,

    Those answers look correct given a small tolerance because of numerical truncation to the given number of digits.
     
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