# Kirchoffs law

Discussion in 'Homework Help' started by amilton542, Nov 18, 2010.

1. ### amilton542 Thread Starter Active Member

Nov 13, 2010
494
64
im struggling with kirchoffs law and find it hard to understand. i got two supplys in parallel,8v and 10v.on the negative side of the 8v supply there is a 4Ω resistor, on the negative side of the 10v supply there is a 6Ω resistor, the branch between the two supplys on the positive side is a 1Ω resistor and to the right hand side of the 10V supply is a leg of its own with a 10Ω resistor with no supply, so far ive for 8= and 10= LOL

2. ### s3b4k Member

Feb 15, 2010
38
0
can you post an image of the circuit it would be easier to understand

3. ### amilton542 Thread Starter Active Member

Nov 13, 2010
494
64
il try and explain it abit better so you can draw it.imagine a 3 leg parrallel network but so each leg is VERTICAL.In the middle leg theres a 10v supply,underneath the supply is a 6Ω resistor. on the left leg theres an 8v supply,underneath the supply is a 4Ω resistor.the 3rd leg on the right has a 10Ω resistor only. The branch on the positive side of the two supplys has a 1Ω resistor

4. ### mikelynch Member

Jun 30, 2007
23
0
is this correct

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5. ### mikelynch Member

Jun 30, 2007
23
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Assuming circuit is ok. Is the working below correct anyone ?

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