Kirchoffs law

Discussion in 'Homework Help' started by amilton542, Nov 18, 2010.

  1. amilton542

    Thread Starter Active Member

    Nov 13, 2010
    494
    64
    im struggling with kirchoffs law and find it hard to understand. i got two supplys in parallel,8v and 10v.on the negative side of the 8v supply there is a 4Ω resistor, on the negative side of the 10v supply there is a 6Ω resistor, the branch between the two supplys on the positive side is a 1Ω resistor and to the right hand side of the 10V supply is a leg of its own with a 10Ω resistor with no supply, so far ive for 8= and 10= LOL
     
  2. s3b4k

    Member

    Feb 15, 2010
    38
    0
    can you post an image of the circuit it would be easier to understand
     
  3. amilton542

    Thread Starter Active Member

    Nov 13, 2010
    494
    64
    il try and explain it abit better so you can draw it.imagine a 3 leg parrallel network but so each leg is VERTICAL.In the middle leg theres a 10v supply,underneath the supply is a 6Ω resistor. on the left leg theres an 8v supply,underneath the supply is a 4Ω resistor.the 3rd leg on the right has a 10Ω resistor only. The branch on the positive side of the two supplys has a 1Ω resistor
     
  4. mikelynch

    Member

    Jun 30, 2007
    23
    0
    is this correct[​IMG]
     
  5. mikelynch

    Member

    Jun 30, 2007
    23
    0
    Assuming circuit is ok. Is the working below correct anyone ?
    [​IMG]
     
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