can you explain how you are do loop 2 (kirchhoff's rules) ?I3 = I1 + I2
10 = 2I1 + 6I3 +4I1 = 2I1 + 6I1 + 6I2 + 4I1 = 12I1 + 6I2
15 = 6I3 + 8I2 = 6I1 + 6I2 + 8I2 = 6I1 + 14I2
Can you solve it from there?
No, in this circuit you have only one loop.I use 2 methods in this circuit but the result not same
I think the first method is true and second method is wrong
please sir can you explain how I knew currents direction in any circuits?
View attachment 72646,
Very strange because I get I = 5/6A = 0.833Abtw- I think this problem is a trick question. I compute the current to be zero.
Jony,...
Very strange because I get I = 5/6A = 0.833A
Isn't 2Vx is a voltage controlled voltage source?Jony,
Do you agree that if I = 5/6, then V(x)-V(y) = I/2 = (5/6)/2 = 0.416667V?
I took it as being a voltage-controlled current-source with a transconductance of 2. That is why I got I = 0A.Isn't 2Vx is a voltage controlled voltage source?
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