KCL and KVL

Discussion in 'Homework Help' started by John Ramelb, Feb 23, 2014.

  1. John Ramelb

    Thread Starter New Member

    Feb 2, 2014
    26
    0
    http://i.imgur.com/IDrSyCY.png ( THe VOLTAGE AT V1 is same as V2 I mean the positive terminal and negative terminal Is just like V2 I didnt see that when I editin in paint.)


    please help me deal this problem. I solve this problem but I don't know where I my solution got wrong.. I try multisim to check my answer but in Resistor 10 it measure 10 amps in multisim. I dont know where I got wrong in my solution. Please help me. PS I dont want to use mesh/nodal . I just want to master the Kirchoff's law Thanks to all of you !!!!

    I came up with my solution.

    loop A:
    100 V - 10(I1) - 5(I2) = 0
    10(I1) + 5(I2) = 100 V

    loop B
    50 V - 2(I1 - I2) - 2(I3) + 5(I2) = 0 (* -1 SO THAT I WILL GET POSITIVE VALUE OF I1)
    2(I1) - 7(I2) + 2(I3) = 50V

    loop C:
    50V - 3(I1 - I2 - I3) + 2(I3) =0
    3(I1) -3(I2) -5(I3) = 50 V

    USING DETERMINANTS I GET THE VALUE OF D AS:
    (I1) (I2) (I3) (V)
    10 5 0 | 100
    2 -7 2 | 50
    3 -3 -5 | 50

    D= 490

    SOLVING FOR I1 USING DETERMINANT

    D1 =
    100 5 0
    50 -7 2
    50 -3 -5

    D1 = 5850
    I1 = D1/ D = 5850/ 490 = 11.938 A

    D2 =
    10 100 0
    2 50 2
    3 50 -5

    D2 = -1900
    I2 = D2/D = -1900/490 = -3.8775 A

    D3 =
    10 5 100
    2 -7 50
    3 -3 50

    D3 = -250
    I3 = D3/D = -250/490 = -0.510 A

    let me know where did i got wrong . I just want to Solve this using KVL and KCL please help me thanks !!!!!
     
    Last edited: Feb 23, 2014
  2. anhnha

    Active Member

    Apr 19, 2012
    774
    48
    Last edited: Feb 23, 2014
  3. anhnha

    Active Member

    Apr 19, 2012
    774
    48
    Last edited: Feb 23, 2014
  4. anhnha

    Active Member

    Apr 19, 2012
    774
    48
    I guess you got 10A through the 10 Ohms resistor because you reversed V2 in your simulation.
     
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