Karnaugh Maps, Boolean Expressions etc.

Discussion in 'Homework Help' started by Nitrag, Sep 16, 2007.

  1. Nitrag

    Thread Starter New Member

    Sep 16, 2007
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    Hi all, first time poster..Anywho have a couple questions about my hw.

    How do you convert a Boolean Expression to a karnaugh map? I first had to draw the circuit using the boolean expression. now it wants me to draw a karnaugh map. How do I go about doing this? Do I use DeMorgan's?

    Code ( (Unknown Language)):
    1.  
    2. f(a,b,c)=(a+c)(b'+c)(a'+b)
    3.  
     
  2. hgmjr

    Moderator

    Jan 28, 2005
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    214
  3. Nitrag

    Thread Starter New Member

    Sep 16, 2007
    8
    0
    I read both but it's still not clicking. The function isn't in a form that I can translate from boolean to k-map.

    Is there a way to get it to a'b'c+c'b'a form? I don't know how to work with (a+b)
     
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