Is this correct? Converting expression to NAND

WBahn

Joined Mar 31, 2012
30,045
No.

What you are basically trying to claim is that (a·b)' = (a'·b'), and it doesn't.

Even if it did, you still wouldn't be finished because you would need to express each of the factors in NAND form.
 

RBR1317

Joined Nov 13, 2010
714
Whenever there is a Sum of Products expression that must be implemented with NAND gates, the only operation that must be applied to the SOP is double negation and a single level application of DeMorgan. However, if the SOP expression must be minimized to a simpler SOP, then that must be accomplished prior to the double negation. If a K-map is disallowed for the minimization, then just perform a Boolean minimization. A K-map is not necessary but can provide insight for the Boolean minimization. If I were in your situation, I would perform the Boolean minimization with a K-map on the side - and claim a flash of insight came from imbibing mass quantities.
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