Hi guys, just hoping you could help clarify a few things for me.
The questions are based off this data sheet: http://www.utm.edu/staff/leeb/LM301.pdf
and this circuit:
1. Estimate \(A_{o}, \sigma\), and GBP for the LM301A.
\(A_{o} = \frac{v_{o}}{v_{+}-v_{-}}\)
The data sheet specifies the typical input offset voltage as 2.0mV and maximum of 7.5mV. So in the most extreme case, \(v_{+}-v_{-} = 7.5mV\)
The power supply is 15V, so the highest we could expect \(v_{0}\) to be is 15V. (Not sure if I'm going about that the right way).
As for σ (the open-loop bandwidth), with the supply voltage of 15V, the voltage gain is guaranteed to be 88dB at minimum. Then reading off the Open Loop Frequency Response graph, the frequency is approximately 10Hz with a capacitor value of 30pF, which I believe we will be using.
GBP = \(A_{o}\sigma\)
2. What is the approximate input impedance of the amplifier circuit (as seen by the source \(V_{i}\))
Should I assume an ideal op-amp, and that \(v_{-}\) is a virtual ground, and therefore the input impedance as seen from \(V_{i}\) is simply \(R_{i}\)?
Any input would be much appreciated, it's been a few years since I last did any work involving circuits. Thanks!
The questions are based off this data sheet: http://www.utm.edu/staff/leeb/LM301.pdf
and this circuit:
1. Estimate \(A_{o}, \sigma\), and GBP for the LM301A.
\(A_{o} = \frac{v_{o}}{v_{+}-v_{-}}\)
The data sheet specifies the typical input offset voltage as 2.0mV and maximum of 7.5mV. So in the most extreme case, \(v_{+}-v_{-} = 7.5mV\)
The power supply is 15V, so the highest we could expect \(v_{0}\) to be is 15V. (Not sure if I'm going about that the right way).
As for σ (the open-loop bandwidth), with the supply voltage of 15V, the voltage gain is guaranteed to be 88dB at minimum. Then reading off the Open Loop Frequency Response graph, the frequency is approximately 10Hz with a capacitor value of 30pF, which I believe we will be using.
GBP = \(A_{o}\sigma\)
2. What is the approximate input impedance of the amplifier circuit (as seen by the source \(V_{i}\))
Should I assume an ideal op-amp, and that \(v_{-}\) is a virtual ground, and therefore the input impedance as seen from \(V_{i}\) is simply \(R_{i}\)?
Any input would be much appreciated, it's been a few years since I last did any work involving circuits. Thanks!