Revered Members,
Please go through my attachment. When the Cell is in open circuit, voltmeter connected in parallel gives the EMF of the cell and and when the circuit is closed, by adding an external resistance in the circuit, voltmeter gives slightly less value than the previous occasion when measured in open circuit, due to the internal resistance of the cell. V = E - Ir. Here r is the internal resistance of the cell and i have drawn that resistance bellow battery. But why the polarity is opposite to that of battery polarity?
Please go through my attachment. When the Cell is in open circuit, voltmeter connected in parallel gives the EMF of the cell and and when the circuit is closed, by adding an external resistance in the circuit, voltmeter gives slightly less value than the previous occasion when measured in open circuit, due to the internal resistance of the cell. V = E - Ir. Here r is the internal resistance of the cell and i have drawn that resistance bellow battery. But why the polarity is opposite to that of battery polarity?
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