Instruction Word Format

Discussion in 'Homework Help' started by CSharpque, Dec 11, 2011.

  1. CSharpque

    Thread Starter Member

    Sep 23, 2011
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    0
    Hello
    I have two question in my paper

    Write down zero address and one address instruction for X=(A+b)*(C+d)/(E-F)

    I know format of both instruction For one address instruction format id
    op code and address part
    and for two address instruction format
    op code
    so how can write this can anyone explain this?

    Second question
    Write a program to evaluate arithmatic statement x=((A*B)+(C*D-E))/(A+B) - using general register computer with three address instruction format and accumulator type computer with one address instruction format.
     
  2. Papabravo

    Expert

    Feb 24, 2006
    10,144
    1,790
    In a zero address machine there is a pushdown stack. All unary operations e.g. negate or comliment, operate on the TOS (Top of Stack). All binary operations e.g. add, subtract, or multiply, use the top two elements of the stack and put the result back on the stack.

    Checkout Polish Postfix notation as an unambiguous way to write any expression. The code for such a machine fit nicely into the zero address format.
     
  3. CSharpque

    Thread Starter Member

    Sep 23, 2011
    40
    0
    i got answer for question one and concept is same as u said thank for answer
    and anyone help me how to solve question 2 i can't understand what question 2 said
     
  4. Papabravo

    Expert

    Feb 24, 2006
    10,144
    1,790
    A three address format has a operand#1, operand#2, and a result. No intermediate registers are required to do any computation.

    In a one address machine there is a general purpose register called an "Accumulator" that is an implied operand along with the single memory address contained in the instruction.
     
  5. CSharpque

    Thread Starter Member

    Sep 23, 2011
    40
    0
    i have preapre answer of second question

    For three address instruction
    MUL t1,A,B
    MUL t2,C,D
    SUB T3,T2,E
    Add T4,T1,T3
    ADD T5,A,B
    DIV X,T4,T5

    One address instruction
    LDA A
    ADD B
    STA T1
    LDA C
    MUL D
    SUB E
    ADD T2
    LDA A
    ADD B
    DIV T2
    STR X

    iS IT RIGHT?
     
  6. CSharpque

    Thread Starter Member

    Sep 23, 2011
    40
    0
    any one tell me mi right?
     
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