Inductor

Discussion in 'Homework Help' started by jstrike21, Oct 8, 2009.

  1. jstrike21

    Thread Starter Member

    Sep 24, 2009
    104
    0
    The current in an L=103microHenry inductor is given as:
    iL(t)=0 for t less than or equal to 0
    iL(t)=25te^(-7t) for t is greater than 0 seconds

    Find voltage at 25 milliseconds.

    What I have:
    v=L(di/dt)
    I took the derivative of iL(t)=25te^(-7t) and got (25-175t)e^(-7t) so...
    v(t)=.000103*(25-175t)e^(-7t)
    and just plug in .025 for t to find out the voltage at 25 milliseconds

    is this right?
     
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    5,448
    782
    That's correct.
     
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