according to v=L(di/dt), when J1 changes from on to off, I can understand that a huge back emf is generated by the inductor.
my question is, when J1 change from off to on, inductor will briefly oppose the change in current from zero to some magnitude, why? Isn't it supposed to give a huge opposite emf as well?
(it doesn't explain in the DC\Inductor section of this site)