# inductor dc steady-state problem

Discussion in 'Homework Help' started by cuixinghe, Apr 30, 2016.

1. ### cuixinghe Thread Starter New Member

Apr 30, 2016
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0
Hi, I was working on this problem, but get confused.

What I already Known:
For DC steady-state, inductors become short ckts. But in this problem, there are two inductors in parallel. I am confused about how the current flow through each inductors.

The problem is shown in the attachment.
Thank you for your times!

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2. ### shteii01 AAC Fanatic!

Feb 19, 2010
3,505
512
Step 1.
Assume that the directions shown in the circuit are correct.

Step 2.
Solve what they ask you to solve.

Step 3.
If some of your currents have negative sign, that tells you that assumption you made in Step 1 was wrong, so just switch the current direction and remove the negative sign.

3. ### cuixinghe Thread Starter New Member

Apr 30, 2016
4
0
Thank you for answering my question. What I don't understand here is when the inductors become short ckt, how the current flow through each one of them. Since they are in parallel, I am not really sure which is the one that current actually flow through.

4. ### shteii01 AAC Fanatic!

Feb 19, 2010
3,505
512
Which part of the hint, that they gave you, you did not understand?

5. ### cuixinghe Thread Starter New Member

Apr 30, 2016
4
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I don't really understand what does "i1 and i2 are time varying at first" mean. Does that information help solving the question?

6. ### shteii01 AAC Fanatic!

Feb 19, 2010
3,505
512
It means that current is not constant. At some point in the past you had a circuit that did not have any sources, the inductors were discharged. Then you connected the current sources, the current start to flow out of current sources and entering the inductors, BUT! This process IS NOT instantaneous! It takes time for current to enter the inductor and for inductor to become fully charged. At first there are just a few electrons and inductor starts showing a weak magnetic field, then there is a small stream of electrons and the magnetic field becomes stronger, then there is a torrent of electrons and inductor becomes fully charged, and the magnetic field becomes as strong as it can be. This is what they are talking about. Yes, later, much later, the current sources have been connected to the circuit for a long long time and inductors are fully charged and have been fully charged for minutes or hours or days, yes we know that at this stage they act as short, but they ask you to temporarily suspend this knowledge. Go back, take the circuit that has no sources, that has discharged inductors, connect the source, and now apply the knowledge that inductors are charging, in this state they will start with zero current, progress to some value of current and as the current increases, there will be a voltage across the inductor... this voltage is the clue you need to calculate the values of the resistors.

Also. Since you have two sources in the circuit, you might want to use superposition in order to solve the equations.

7. ### cuixinghe Thread Starter New Member

Apr 30, 2016
4
0
I really appreciate your help! I think I know how to do this problem now. Thanks again!

8. ### MrAl Distinguished Member

Jun 17, 2014
2,561
517
Hi,

I guess they are assuming ideal inductors here.

9. ### WBahn Moderator

Mar 31, 2012
18,087
4,917
Yes, they have to make that assumption because they don't model any parasitic elements.