Inductor Book Solution ?

Discussion in 'Homework Help' started by DYLH, Nov 2, 2013.

  1. DYLH

    Thread Starter New Member

    Aug 13, 2013
    28
    1
    See https://www.circuitlab.com/circuit/gej8eb/screenshot/540x405/

    Given
    iA(t) = [0.6 * e ^ (-2t)] A
    iB(t) = [1.2 * e ^ (-2t) - 0.4] A
    i(t) = [1.8 * e ^ (-2t) - 0.4] A

    find = my solution
    v1(t) = -7.2 e ^ (-2t)
    v2(t) = -28.8 e ^ (-2t)
    v(t) = -36 e ^ (-2t)

    book
    v1(t) = -36 e ^ (-2t)
    v2(t) = -7.2 e ^ (-2t)
    v(t) = -28.8 e ^ (-2t)
    reality check: KVL violated: v(t) != v1(t) + v2(t)

    am I misunderstanding something, or is the book solution misprinted?
     
  2. anhnha

    Active Member

    Apr 19, 2012
    773
    45
    Yes, your answer is correct.
    Just use the formula:

    V_{L}(t)  = L \frac{di(t)}{dt}
     
    DYLH likes this.
Loading...