inductive reactance!

Discussion in 'Wireless & RF Design' started by aj_silverthunder, Nov 28, 2009.

  1. aj_silverthunder

    Thread Starter Active Member

    Jun 6, 2009
    116
    0
    guys how do u calculate the value of the rf choke using the inductive reactance formula, XL = 2∏fL .for example here u can see a schematic which transmits in a frequency 100Mhz,there u can see a choke!
    my friend gave me this way to find out the value of choke
    " 10kΩ inductive reactance would be fine.
    That translates to
    XL = 2πfL
    10kΩ = 10000Ω
    10000Ω = 2π(100M)L
    L = 10000 / (2*∏*1e8)
    L = 1e4/ (2*∏*1e8)
    L = (1/6) 1e-4
    L = 0.16e-4
    L = 16e-6
    L = 16µH."
    so there fore the vakue of the choke should be 16μH.
    but can u guys please tell me how did that 10kΩ come from.how did he take the 10KΩ from the circuit! please help me!
     
  2. aj_silverthunder

    Thread Starter Active Member

    Jun 6, 2009
    116
    0
    F=frequency=100Mhz,its the transmitting frequency of the TX
     
Loading...