INDUCTANCE

Discussion in 'Homework Help' started by bujak18, Jan 13, 2009.

  1. bujak18

    Thread Starter Active Member

    Nov 12, 2008
    49
    0
    Determine the total inductance and the circuit current of a 4-H inductor and a 6-H inductor series connected to a 400-Hz, 80-V supply. also determine the voltage across the 4-H inductor.
     
  2. bertus

    Administrator

    Apr 5, 2008
    15,648
    2,346
  3. mik3

    Senior Member

    Feb 4, 2008
    4,846
    63
    If you have two inductors in series the total inductance is the sum of each of the inductors value. In your case is 6+4=10 H.

    The impedance of the total inductance is:

    XL=2*pi*f*L=2*pi*400*10=25.1K

    Thus the current flowing will be:

    I=V/XL=80/25.1K=3.2mA

    The voltage across the 4H inductor:

    XL4=2*pi*f*L=10K

    thus

    VL4=XL4*I=32V
     
  4. bujak18

    Thread Starter Active Member

    Nov 12, 2008
    49
    0
    sry i don't quite understand do you know the exact answer? pls.
     
  5. mik3

    Senior Member

    Feb 4, 2008
    4,846
    63
    The current flowing is 3.2mA and the voltage across the 4H inductor is 32V.
     
  6. bujak18

    Thread Starter Active Member

    Nov 12, 2008
    49
    0
    go to my other threads on this forum pls and see if you can answer them
     
Loading...