induced emf

Thread Starter

lemon

Joined Jan 28, 2010
125
a) The flux linking a coil of 2000 turns falls from 0.25 Wb to zero in 12.0s. What is the magnitude of the induced emf in the coil?

b) The current in one coil of a pair of coils changes at 0.85A/s. Calculate the induced emf in the other coil if this coil is open circuit (no current flows) and the mutual inductance of the pair is 400mH.

Equation: e=-L.di/dt
Where di/dt is the rate of change gradient

Answer:
a) There is a decrease in flux of 0.25Wb in 12s.
The induced emf opposes the current causing it.
This is Lenz's law because it is a negative.

-0.25/12s=-0.02V (2d.p.)
Why do I have a feeling this is completely wrong :rolleyes:
I think I may have used this equation wrongly. -L is the self inductance, right? So is that the flux change?

Think I may need a lot of help here please :confused:
 
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