Impedance Magnitude In Series RLC Circuits

Discussion in 'Homework Help' started by Ryzing, Sep 23, 2010.

  1. Ryzing

    Thread Starter New Member

    Sep 22, 2010
    4
    0
    Hi,

    My problem this time have to do with
    series RLC circuits and it is impedance magnitude. Here is my attempt on the question:

    "R=470 Ohms, L=4 H, C=104µF & e is a 90 V, 9Hz power supply. What is the magnitude of the impedance of the circuit?"

    The solution:

    6.28x9Hzx4 H=226.19 ohms

    1/6.28x9Hzx104µF=170.03 ohms

    226.19-170.03=56.16

    470^2+56.16^2square root= 58.09

    I seem to be lost in this question. Thanks.
     
  2. Ghar

    Active Member

    Mar 8, 2010
    655
    72
    What did you just do there?

    \sqrt{470^2+56.16^2} = \sqrt{220900 +3154} = 473.3 \Omega
     
  3. Ryzing

    Thread Starter New Member

    Sep 22, 2010
    4
    0
    LOL @ myself. Thanks.
     
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