Impedance calculation

Discussion in 'Physics' started by sandhi, Dec 15, 2009.

  1. sandhi

    Thread Starter New Member

    Jan 28, 2009
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  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
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    Not quite sure what the point of the exercise is, but I get the following relationship for Rf (which I haven't double checked)

    Rf=\frac{jXc}{1-\frac{jXc}{Rm+Rv-\frac{UgRm}{Um}}}

    where

    Xc=\frac{1}{\omega Ce}
     
  3. t_n_k

    AAC Fanatic!

    Mar 6, 2009
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    782
    A point to note (if the relationship I gave is indeed correct) is that Rf should be purely resistive and hence the imaginary term(s) in the derived value of Rf should be zero. This means Um would have a complex value such that the aforementioned condition is met.
     
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