I dont really want to create a new thread for this simple question so I just found this thread that would correspond to my problem.
We are covering Boolean algebra right now and here is my problem:
\(A \cdot \overline{A} \cdot B + A \cdot B \cdot \overline{C} + A \cdot B \cdot \overline{B}=A\cdot B\cdot \overline{C}\)
I need to discover what rule has been used in this simplification but I don't see how could they achieve that output. Please help me to identify. Thanks.

 

We really don't mind new threads, which is why you have one. Hijacked threads get really hard to follow.

This is the old thread - http://forum.allaboutcircuits.com/showthread.php?t=1647

 

Think about this: When a variable \({X}\) is 1, \(\bar{X}\) is 0. When \(\bar{X}\) is 1, \({X}\) is 0. And what is the result of 1 AND 0?

 

It just cleared in my mind that \(A \cdot \bar{A} \cdot B=0\) and \(A \cdot B\cdot\bar{B}=0\)
Thanks Georacer, I used your tactic.