I want to calculate the Path loss exponent and variance given below are the details.

Discussion in 'Wireless & RF Design' started by redhat33, Mar 7, 2013.

  1. redhat33

    Thread Starter New Member

    Mar 7, 2013
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    x= 38.5; y= -5.2;
    x= 45.73; y= 11.28;
    x= 45.73; y= 1.69;
    x= 43.47; .y= 20.17;
    (Gain)gtgr=1 , lamba(wavelength)=0.125
    d=1,L=1
    p(t)=18dBm
     
  2. redhat33

    Thread Starter New Member

    Mar 7, 2013
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    A liitke help would be appreciated guys !!
     
  3. bertus

    Administrator

    Apr 5, 2008
    15,648
    2,346
    Hello,

    You only give some coordinates and a wavelength.
    You do not show anything you have tried or background information on the question.

    Have a look in the wiki:
    http://en.wikipedia.org/wiki/Path_loss

    Bertus
     
  4. redhat33

    Thread Starter New Member

    Mar 7, 2013
    4
    0
    Hello Bertus

    These are the coordinates of the system.
    f=2.4Ghz,GtGr=1,Pt=18dBm,d=1m,L=1. The wavelength what you find is uniform for all the co-ordinates as they transmit uniform frequency so the wavelength is lamba=0.125

    x= 38.5; y= -5.2;
    x= 45.73; y= 11.28;
    x= 45.73; y= 1.69;
    x= 43.47; y= 20.17;
    x= 68.93; y= 9.42;
    x= 33.83; y= 5.74;
    x= 32.14; y= 24.92

    What I did was substituted the values on f and d and GtGr in Free space propagation model and found it as 40dB but after this i have no idea how to proceed.

    Based on Rappaport book pg.no 143 I tried calculating the pathloss and variance but there is something missing and I dont know what it is !
     
  5. redhat33

    Thread Starter New Member

    Mar 7, 2013
    4
    0
    to find the distance between the co-ordinates I used the formula
    dist = sqrt( (x2 - x1)**2 + (y2 - y1)**2 )
     
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