# I want to calculate the Path loss exponent and variance given below are the details.

Discussion in 'Wireless & RF Design' started by redhat33, Mar 7, 2013.

1. ### redhat33 Thread Starter New Member

Mar 7, 2013
4
0
x= 38.5; y= -5.2;
x= 45.73; y= 11.28;
x= 45.73; y= 1.69;
x= 43.47; .y= 20.17;
(Gain)gtgr=1 , lamba(wavelength)=0.125
d=1,L=1
p(t)=18dBm

2. ### redhat33 Thread Starter New Member

Mar 7, 2013
4
0
A liitke help would be appreciated guys !!

3. ### bertus Administrator

Apr 5, 2008
15,648
2,346
Hello,

You only give some coordinates and a wavelength.
You do not show anything you have tried or background information on the question.

Have a look in the wiki:
http://en.wikipedia.org/wiki/Path_loss

Bertus

4. ### redhat33 Thread Starter New Member

Mar 7, 2013
4
0
Hello Bertus

These are the coordinates of the system.
f=2.4Ghz,GtGr=1,Pt=18dBm,d=1m,L=1. The wavelength what you find is uniform for all the co-ordinates as they transmit uniform frequency so the wavelength is lamba=0.125

x= 38.5; y= -5.2;
x= 45.73; y= 11.28;
x= 45.73; y= 1.69;
x= 43.47; y= 20.17;
x= 68.93; y= 9.42;
x= 33.83; y= 5.74;
x= 32.14; y= 24.92

What I did was substituted the values on f and d and GtGr in Free space propagation model and found it as 40dB but after this i have no idea how to proceed.

Based on Rappaport book pg.no 143 I tried calculating the pathloss and variance but there is something missing and I dont know what it is !

5. ### redhat33 Thread Starter New Member

Mar 7, 2013
4
0
to find the distance between the co-ordinates I used the formula
dist = sqrt( (x2 - x1)**2 + (y2 - y1)**2 )