I need help with this transfer function.

Discussion in 'Homework Help' started by dimatizer, Dec 1, 2012.

  1. dimatizer

    Thread Starter New Member

    Dec 1, 2012
    3
    0
    [​IMG]

    Vout is across Vc2
     
    Last edited: Dec 1, 2012
  2. WBahn

    Moderator

    Mar 31, 2012
    17,757
    4,800
    #1) What help do you need?

    #2) What efforts have you made to work the problem?
     
  3. dimatizer

    Thread Starter New Member

    Dec 1, 2012
    3
    0
    G(s)= (3RCS+(RCS)^2+1)/[(SC)^2)(RSC+2)^2]

    I achieved this answer by doing VC2=I2/CS=(Inot/cs)(1/SRC+2) and
    Vin=(Inot)(Z) were Z is the equivalent impedance and my Transfer function is Vc2/Vin

    I need help figuring out what I'm doing wrong because I don't believe I'm getting the right answer
     
  4. WBahn

    Moderator

    Mar 31, 2012
    17,757
    4,800
    Without commenting (yet) one whether you are right or wrong, why is it that you believe you aren't getting the right answer? What have you done to check you answer?
     
  5. dimatizer

    Thread Starter New Member

    Dec 1, 2012
    3
    0
    i found the transfer function of just the left circuit to be 1/(1+RCS) . i believe the right answer should be [(1/(1+RCS))(1/(1+RCS))]
     
  6. blah2222

    Well-Known Member

    May 3, 2010
    554
    33
    Also, it would help if you used LaTeX formatting to read these equations easier.

    http://en.wikibooks.org/wiki/LaTeX/Mathematics

    <br />
G(s)\ =\ \frac{3RCS+(RCS)^{2}+1}{(SC)^{2}(RSC+2)^{2}}<br />

    Is a lot easier to read than:

    G(s)= (3RCS+(RCS)^2+1)/[(SC)^2)(RSC+2)^2]

    Now, I have not verified if this is indeed correct but for the sake of making it easier to read. Click "quote" to see the formatting.
     
  7. ramancini8

    Member

    Jul 18, 2012
    442
    118
    Look to the left of the dotted line and calculate the Thevenin equivalent circuit. Replace the stuff to the left with the TEC, and use the voltage divider rule to calculate the voltage across C2.
     
Loading...