Vout is across Vc2

 

#1) What help do you need?

#2) What efforts have you made to work the problem?

 

G(s)= (3RCS+(RCS)^2+1)/[(SC)^2)(RSC+2)^2]

I achieved this answer by doing VC2=I2/CS=(Inot/cs)(1/SRC+2) and
Vin=(Inot)(Z) were Z is the equivalent impedance and my Transfer function is Vc2/Vin

I need help figuring out what I'm doing wrong because I don't believe I'm getting the right answer

 

Without commenting (yet) one whether you are right or wrong, why is it that you believe you aren't getting the right answer? What have you done to check you answer?

 

i found the transfer function of just the left circuit to be 1/(1+RCS) . i believe the right answer should be [(1/(1+RCS))(1/(1+RCS))]

 

Also, it would help if you used LaTeX formatting to read these equations easier.

http://en.wikibooks.org/wiki/LaTeX/Mathematics

\(
G(s)\ =\ \frac{3RCS+(RCS)^{2}+1}{(SC)^{2}(RSC+2)^{2}}
\)

Is a lot easier to read than:

G(s)= (3RCS+(RCS)^2+1)/[(SC)^2)(RSC+2)^2]

Now, I have not verified if this is indeed correct but for the sake of making it easier to read. Click "quote" to see the formatting.

 

Look to the left of the dotted line and calculate the Thevenin equivalent circuit. Replace the stuff to the left with the TEC, and use the voltage divider rule to calculate the voltage across C2.