1) is x(t).δ(1)=x(t).δ(3)? by using property δ(-t)=δ(t) =»δ(-t+to)=δ(t+to)
2).The expression δ(-t-t0)*x(t0-t), = ?(where * stands for convolution )
2).The expression δ(-t-t0)*x(t0-t), = ?(where * stands for convolution )
i have two confusion
- Thread starter devnarayan
- Start date
