# I have problem in op-amp can any help me please

Discussion in 'General Electronics Chat' started by ksalatawi, Apr 19, 2005.

1. ### ksalatawi Thread Starter Member

Nov 29, 2004
21
0
question in this attachment

2. ### pebe AAC Fanatic!

Oct 11, 2004
628
3
This looks like homework. If so, you should have been taught about op-amps before being set this excercise. So which part don't you understand?

3. ### David Bridgen Senior Member

Feb 10, 2005
278
0
The two opamps on the left need not contribute any gain. They need to provide only an inversion of sign.

The right hand one is the summer.

Remember that the ratio of the feedbak R to the input R gives the voltage gain from an input to the output. This is true for eachof the three stages.
You need to do the simple arithmetic for each of the three inputs.

4. ### ksalatawi Thread Starter Member

Nov 29, 2004
21
0
thank you but
how can i find the value of the resistors
If i find that R2R8/R1R3=3 and
R5R8/R4R6=2 and R8/R7=4

5. ### dragan733 Senior Member

Dec 12, 2004
152
0
Hi ksalatawi,
1. The solution is that:
R2R8/R1R3=3
R5R8/R4R6=2
R8/R7=4
We have 8 unknown resistors and only three equations.

2. Each op -amp. amplifies and inverts the input signal

3.

3V1+2V2-4V3=15
2V1+2*3-4*1=15
V1=4,33V
3V1+2*3-4*1=-15
V1=-5,67V
Then the range of V1 for linear operation is: -5,67V until 4,33V

6. ### ksalatawi Thread Starter Member

Nov 29, 2004
21
0
thaaaaaaaaank you very much dragan i missed you

7. ### ksalatawi Thread Starter Member

Nov 29, 2004
21
0
can i find the value of each resistor

8. ### dragan733 Senior Member

Dec 12, 2004
152
0
Thank you ksalatawi. The answer I gave you also on your E-mail.
1. The solution is that:
R2R8/R1R3=3
R5R8/R4R6=2
R8/R7=4
We have 8 unknown resistors and only three equations. That means we can select for example:
R7=1K Ω , R1=1K Ω , R3=1K Ω , R4=1K Ω , R6=1K Ω then R8=4K Ω , R5=500 Ω, R2=750 Ω
or for example:
R8=4KΩ, R4=1K Ω , R6=2K Ω , R2=3K Ω ; R3=2K Ω then: R7=1K Ω , R5=1K Ω , R1=2K Ω
Therefore there are infinity combinations