I do not know how to draw a Phasor diagram! Help me!

Discussion in 'Homework Help' started by kingcoinz21, Aug 26, 2010.

Aug 26, 2010
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2. Papabravo Expert

Feb 24, 2006
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The two impedances are in series so you draw 10 ohms along the positive x-axis which is the real axis and you draw 15 ohms alond the vertical axis which is the imaginary or jω-axis. The impedance is the vector sum of 10 + j15
Code ( (Unknown Language)):
1.
2. |Z] = SQRT(10^2 + 15^2) = SQRT(325) ≈ 18
3. arg(Z) = tan^-1(15/10) ≈ 56.3°
4.
Was that what you were looking for?

3. kingcoinz21 Thread Starter New Member

Aug 26, 2010
2
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Yes! that helped me a lot. I had that down on my paper, but was unsure if I was correct. Thank you!

I have another question also.
Circuit:
http://i33.tinypic.com/331ese9.png

How do i find the ZT, Degrees, VR, VC, and VL?

4. Papabravo Expert

Feb 24, 2006
10,021
1,757
XL is ploted along the positive jω-axis and Xc is plotted along the negative jω-axis so:
Code ( (Unknown Language)):
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2. 170 - 90 = 80
3.
so the capacitor in series with the inductor looks like an inductor with a smaller reactance namely 80 ohms. From there it is just like the previous problem