I do not know how to draw a Phasor diagram! Help me!

Discussion in 'Homework Help' started by kingcoinz21, Aug 26, 2010.

  1. kingcoinz21

    Thread Starter New Member

    Aug 26, 2010
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  2. Papabravo

    Expert

    Feb 24, 2006
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    The two impedances are in series so you draw 10 ohms along the positive x-axis which is the real axis and you draw 15 ohms alond the vertical axis which is the imaginary or jω-axis. The impedance is the vector sum of 10 + j15
    Code ( (Unknown Language)):
    1.  
    2. |Z] = SQRT(10^2 + 15^2) = SQRT(325) ≈ 18
    3. arg(Z) = tan^-1(15/10) ≈ 56.3°
    4.  
    Was that what you were looking for?
     
  3. kingcoinz21

    Thread Starter New Member

    Aug 26, 2010
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    Yes! that helped me a lot. I had that down on my paper, but was unsure if I was correct. Thank you!

    I have another question also.
    Circuit:
    http://i33.tinypic.com/331ese9.png

    How do i find the ZT, Degrees, VR, VC, and VL?
     
  4. Papabravo

    Expert

    Feb 24, 2006
    10,144
    1,791
    XL is ploted along the positive jω-axis and Xc is plotted along the negative jω-axis so:
    Code ( (Unknown Language)):
    1.  
    2. 170 - 90 = 80
    3.  
    so the capacitor in series with the inductor looks like an inductor with a smaller reactance namely 80 ohms. From there it is just like the previous problem
     
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