i cubed = real number?

Thread Starter

strantor

Joined Oct 3, 2010
6,798
I'm doing online homework, and the question is
Find all solutions of the equation. Check your solutions in the original equation. (Enter your answers as a comma-separated list.)

x3 + 512 = 0
The correct answers, verified by the system, are:
\({-8, 4-4\sqrt{3}i, 4+4\sqrt{3}i}\)

I don't understand how the last 2 are correct, because i X i = -1, so \((4+4\sqrt{3}i ) * (4+4\sqrt{3}i )\) should be a real number, but \((4+4\sqrt{3}i ) * (4+4\sqrt{3}i ) * (4+4\sqrt{3}i )\)should be an imaginary number, correct?
 

Thread Starter

strantor

Joined Oct 3, 2010
6,798
DOH! Yep, they sure do.
Thanks

EDIT:
I was also wrong about \((4+4\sqrt{3}i ) * (4+4\sqrt{3}i )\) being a real number.
 

WBahn

Joined Mar 31, 2012
30,062
Just want to chime and say that it's good to see someone asking "does the answer make sense?", and that includes asking it of the "book's" answers, since the book will be wrong from ime to time.
 
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