I can't figure this out! Please help

Discussion in 'Homework Help' started by wilmania, Nov 7, 2006.

  1. wilmania

    Thread Starter New Member

    Nov 7, 2006
    2
    0
    I have gone thru all my examples to find a solution to this problem... but no matter what I do I seem to get it wrong... I need help on how to simplify the following:


    (xy’ + w’z)(wx’ + yz’)

    This is what I have:
    = xy'wx' + xy'yz' + w'zwx' + w'zyz' (Distributive)
    = x' + y + w' + xx' + y + y' + zw + z' + w' + xw + z' + y' + z (DeMorgan's)
    = .... (I keep simplifying)
    = 1 (I know this isn't right...)
     
  2. Papabravo

    Expert

    Feb 24, 2006
    9,905
    1,723
    After applying FOIL(First, Outer, Inner, Last) you should note that each term evaluates to zero.
    Code ( (Unknown Language)):
    1.  
    2. xywx'  -> 0 because xx' = 0
    3. xy'yz  -> 0 because y'y = 0
    4. w'zwx' -> 0 because w'w = 0
    5. w'zyz' -> 0 because zz' = 0
    6.  
    Right?
     
  3. Dave

    Retired Moderator

    Nov 17, 2003
    6,960
    143
    I'm with Papabravo on this one, from your line of analysis for the Distributive property you will find that the relations Papabravo has stated are present. Since you can't have something AND not-something then the expression is impossible (or in Boolean speak "false"/"0").

    Dave
     
  4. wilmania

    Thread Starter New Member

    Nov 7, 2006
    2
    0
    Fair enough... Thank you guys!
     
  5. Papabravo

    Expert

    Feb 24, 2006
    9,905
    1,723
    de nada - your're welcome
     
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