i want to turn on a pump that uses 12v,
is there a switch that have two inputs whenever the first input is on which is 5v, then the second input 12v will turn the output on and take the voltage of 12v.

 

That is hard to follow. Have you considered a relay to control the pump? Why is there a first input and then a second?

 

what i wanted to say is i will have 12v input and another input from the circuit. if the circuit which is 5v in On then the pump will turn On, using the 12v power supply.

 

What is the source of the 5V input...logic?...microcontroller?...? What is the current or wattage rating of the 12V pump? Depending on your circuits, you might be able to use a resistor and transistor...or a relay.

Ken

 

i will use a circuit that uses logic gates. Also i will use microcontroller. the pump uses 12v and 3 amps.

 

In that case I would use a relay to isolate the 12V motor supply from the 5V logic/microcontroller supply. Use a 1K resistor and a 2N3904 transistor as a common emitter amplifier to drive a 5V relay. Place a 1N4001 diode across the relay coil, with the cathode to the +5V and the anode to the transistor's collector.

Ken

 

here is the drawing of the circuit!
the sensor will send a voltage signal and compare it with a specific voltage if the voltage signal from the sensor is lower then the circuit will turn on the pump(which is the lamp in this case)
but i couldn't get it work.

 

The switching circuit beyond the 331 is OK.

Ken

 

but is there anything wrong in the design!! because it doesn't work!!

 

Hello,

Make a voltage divider on the Vcc at the + input of the 331.
That way there is a switching point.

Now you are comparing Vcc with Vcc wich is not working.

Bertus

 

You need to power the relay coil from +5V. You can't switch an AC load with a transistor.
What kind of sensor do you have?

 

See attached:

 

See attached:

The input circuitry still won't work. First, we don't know his sensor characteristics, and second, the input voltage range of the LMV331 does not extend to the positive supply voltage. Even if it did, a comparator output is indeterminate when the inputs are equal.

 

I didn't look up the part, I thought he was literally using a switch with a low-power opamp that could go close to GND.

For a comparator, check the datasheet (or other) application circuits and use hysteresis.

 

I didn't look up the part, I thought he was literally using a switch with a low-power opamp that could go close to GND.

For a comparator, check the datasheet (or other) application circuits and use hysteresis.

Close to GND isn't the problem. LMV331 inputs can go 0.1V below GND, but it will only work when the inputs are more than 0.8V below the positive rail.

 

the sensor i'm going to use is for soil moisture, when the voltage comes from the sensor less than the v+ which i don't know what is the right moisture in other word the right voltage range to set for the circuit to send High signal.
ok, here what i have done so far!
i did a voltage divider, and connected the power supply to 5v instead of 12v.
and it still doesn't work!! am i using the right relay!!

 

the sensor i'm going to use is for soil moisture, when the voltage comes from the sensor less than the v+ which i don't know what is the right moisture in other word the right voltage range to set for the circuit to send High signal.
ok, here what i have done so far!
i did a voltage divider, and connected the power supply to 5v instead of 12v.
and it still doesn't work!! am i using the right relay!!

Look at the datasheet of the comparator. It has an open collector output. You need a pullup resistor.

 

How to construct the pull-up resistor!

 

How to construct the pull-up resistor!

This is how you do it if you don't need any hysteresis. I suspect you will need hysteresis if you build hardware, which means you will need some changes.

 

i'm building this project, it's just one part of the project! ^_^, if i do this part correct i will know how to do the rest of it.