Planck constant ,h ?The key to doing the proof is to find the precise relationship between the frequency or wavelength of the spectral line and the chnage in energy level of the electron that emits a photon at that frequency (wavelength)
Hint(s): The frequency times the wavelength is equal to the speed of light. Now go find the "constant of proportionality" between Energy and frequency. This constant is named after a famous Physicist.
Ok..will try..thank youThey are not numerically or obsessionally equal but they state the same principle. Once in terms of energy difference, and once in terms of frequency. Energy and frequency are related proportionally by Planck's constant.
The actual 2-step proof is detailed on Wikipedia.
PS doesn't it feel better to have discovered that yourself with some help and a hint rather than seeing the result?
So I proved by equating the two equation ? and cancel out those same terms ?Yeah. We know that K is 4*pi*epsilon sub 0. We know that E is h times nu and we know that the Rydberg constant can be expressed in terms of h, c, epsilon sub 0, mass and electron charge.
Pick either the energy or the frequency expression and transform one into the other by applying the simple rules of algebra: substitution and multiplying both sides of an equation by the same thing.
For example:
Also remember that h-bar, the reduced Planck's constant is h over 2*pi
- Start with the expression for nu (frequency)
- Substitute an expression for R
- Multiply both side by h
- The LHS (Left Hand Side) should be Energy Difference and the RHS (Right Hand Side) should be the other expression.