# How to display 0 to 15 in to 2 x 7segment?

Discussion in 'Homework Help' started by markosma16, Oct 4, 2016.

1. ### markosma16 Thread Starter New Member

Jul 12, 2015
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I've been trying to work on this but I can't make it. I'm using 74LS93 to display 0 to 15 into 2x 7segment. So far I worked on displaying 10 but after that it'll reset. I ANDed Qb and Qc (4 & 2) and put it in the RESET but instead the ones digit will count up to 15 (not decimal) and reset again.

2. ### markosma16 Thread Starter New Member

Jul 12, 2015
3
0
So the display of the first digit will be like this : 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 then back to 0 again
the 2nd digit will only become 1 when the 1st digit becomes 0. So far 0 to 10 then back to 00 is all I worked.

3. ### hp1729 Well-Known Member

Nov 23, 2015
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If you are really desperate to do this you can use a PROM. The 7493 selects the address of the PROM. The contents of the PROM gives the desired digits. 74S188 or 74S288, or other 32 x 8 PROM.

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4. ### markosma16 Thread Starter New Member

Jul 12, 2015
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Is there any other trick that can I use like putting some logic gates or adding one 7493?

5. ### hp1729 Well-Known Member

Nov 23, 2015
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Another counter would do it. Reset the one's counter at a count of ten and carry that to the ten's counter. Then reset both counters at a count of 1, 5.
But then you have two counters. Why not just use two decade counters.

6. ### MrChips Moderator

Oct 2, 2009
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That is assuming that you are counting a clock signal.
What if there is no clock and the 4-bit binary value is static?

7. ### hp1729 Well-Known Member

Nov 23, 2015
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The ones counter counts up to 9. On the tenth pulse it resets itself to zero and sets the tens counter. On the following sixth count both counters reset.

8. ### hp1729 Well-Known Member

Nov 23, 2015
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Second version. You really don't need the second counter, only one latch. same basic operation.

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