how to convert squarewave to 180 deg out of phase?

Discussion in 'General Electronics Chat' started by jerone, Aug 30, 2008.

  1. jerone

    Thread Starter Member

    Aug 30, 2008
    15
    0
    hi to all. . . im new here and im happy to be a part of this forum.
    i encountered a problem with my design today and seeking for help.
    please help me how to convert a squarewave to 180 deg out of phase. thanks a lot.
     
  2. kubeek

    AAC Fanatic!

    Sep 20, 2005
    4,670
    804
    just invert it.
     
  3. jerone

    Thread Starter Member

    Aug 30, 2008
    15
    0
    thanks a lot. hers another one. . . what should i place in my circuit in order to
    block my input signal and it will only flow after another + half square wave signal passes.this input signal will reset my another circuit but this signal also depends on the + half square wave. what circuit should i use?

    a 555 monostable would do but theres a little problem. output will only be at high after the trigger button's release,not at its first press.

    pls help,thanks.
     
  4. kubeek

    AAC Fanatic!

    Sep 20, 2005
    4,670
    804
    Not sure what you mean, but that could be an AND gate.
     
  5. jerone

    Thread Starter Member

    Aug 30, 2008
    15
    0
    heres the waveform friend. hope you can help me on this. [​IMG]
     
  6. jerone

    Thread Starter Member

    Aug 30, 2008
    15
    0
    heres the waveform friend. hope you can help me on this. [​IMG]
     
  7. kubeek

    AAC Fanatic!

    Sep 20, 2005
    4,670
    804
    Then you need an edge detector for that.
    Is it a part of some digital circuit where clock is involved, or is it analog?
    What is the speed of the clock, or the length of the trigger pulse?
    What type of load is connected to the circuit that will generate the modified trigger?
     
  8. SgtWookie

    Expert

    Jul 17, 2007
    22,182
    1,728
    See the attached for a reasonably simple rising edge gate.

    You might trigger a monostable 555 timer from an output taken at either point "C" or point "D".
     
  9. kubeek

    AAC Fanatic!

    Sep 20, 2005
    4,670
    804
    I must say my initial reply was VERY similar, but then I rather asked more questions :)
     
  10. SgtWookie

    Expert

    Jul 17, 2007
    22,182
    1,728
    It did have similarities. ;) However, the circuit I threw together is basically an integrator, with the negative portion clamped by D1. Since there are four Schmitt-trigger NAND gates on a 4093, didn't hurt to use one as an inverter ;)
     
Loading...