How to convert basic gate to NAND gate

Discussion in 'General Electronics Chat' started by beginner123, Oct 3, 2010.

  1. beginner123

    Thread Starter New Member

    Oct 3, 2010
    1
    0
    How to convert the following boolean expression X = AB + CD + AD' to 2- input NAND gate I had tried alot of time already, research on googles but still don't understand, can anyone help me?

    I only know AB = (AB)' right if convert to NAND gate, so I get this boolean expression [(AB)'(CD)'(AD')']' does this correct? but it still 3 input, how to design the circuit with only 2-input NAND gate.
     
  2. elisettynarendra

    Member

    May 17, 2010
    42
    1
    i will not give the solution rather i will give u a hint.
    take out 'A' common u will be left with A(B+D')+CD . try modifying the equation rather than trying as it is..learn the basics.
    use (AB)'=A'+B'
    a+bc = (a+b)(a+c)
    u will succeed.
     
    romel_emperado likes this.
  3. romel_emperado

    New Member

    Jul 23, 2009
    5
    0
    i forgot the laws of demorgan's law in simplifying that equation...

    just subscribing this thread to know something.. thanks buddy..
     
  4. Wendy

    Moderator

    Mar 24, 2008
    20,765
    2,536
    The example you gave, AB = (AB)', is seriously flawed, you want the output to be the same as it's inverted output? It is like saying 1=-1.
     
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