Hello,

This is the Danelectro Honeytone practice amp circuit. Diodes D1 & D2 are 1N4148 silicon ones. I measured a sine wave output on the oscilloscope and this is what i found:

1) with both diodes REMOVED: pk-pk voltage=5.7V

2) with 1N4148 diodes intact: pk-pk voltage=2.88V

**These voltages were measured at pin1.**

Everyone says they are clipping diodes. I think that too. But, if the diode's forward voltage drop=0.7V, then 2X diodes should be 0.7x2 = 1.4V? Shouldn't the pk-pk voltage with diodes intact be more than 2.88V? Just a little confused here..

 

The diodes have the tone, volume and various filtering around them.

The only place to see what the diodes are doing is by looking at the signal directly across the diodes. It should be near to a square wave at the input levels you were using.

 

I thought this was covered in the other thread (http://forum.allaboutcircuits.com/showthread.php?t=35898) you started????? What did I miss?

As someone else has quoted, "Insanity: doing the same thing over and over again and expecting different results." Albert Einstein

 

The second opamp has a voltage gain of 34 so its output depends on the setting of the tone and volume controls.