# How do I find this current?

Discussion in 'Homework Help' started by no12thward, Jan 11, 2011.

1. ### no12thward Thread Starter Member

Jan 10, 2011
30
0
I am trying to find the current coming out of the Silicon diode here. With an energy source or a given voltage I would be able to, but just the current on on side of the circuit is given. So i am confused on how to the current coming out of the diode, as shown.....

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2. ### hgmjr Moderator

Jan 28, 2005
9,030
214
Use Norton's Theorem to convert the 6mA current source and the 3K resistor in parallel with it into its equivalent voltage and resistance and then I think you will find that the problem becomes a simpler thing to manage.

hgmjr

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3. ### no12thward Thread Starter Member

Jan 10, 2011
30
0
Maybe I'm still confused after converting my current to a voltage source. It looks like just simple Ohms Law after that, But for Id (the current coming out of the silicon diode) I got 2.88mA. Though I don't feel 100% sure about that answer. Does that look right?

4. ### shteii01 AAC Fanatic!

Feb 19, 2010
3,393
497
I used the current divider and I also got 2.883 mA.

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5. ### hgmjr Moderator

Jan 28, 2005
9,030
214
Your answer agrees with mine. If you include a scan of your calculations then we could confirm them.

hgmjr

Last edited: Jan 12, 2011
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6. ### StayatHomeElectronics Well-Known Member

Sep 25, 2008
864
40
Substitute the currents from your calculations back in to see if the voltage in each leg is equal...

3000*0.00288 + 0.7 = 3000*0.00312

If that statement is true, with some small error from approximating answers, than the answers are probably correct.

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