How convert the given expression from SOP to POS

Discussion in 'Homework Help' started by CSharpque, Oct 5, 2011.

  1. CSharpque

    CSharpque Thread Starter Member

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    Sep 23, 2011
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    I have read the other thread and and get rule for converting SOP to POS and that is DeMorgan and Involution. Also get example . From that example i try to convert expression from SOP to POS. So plzzz check is this true?

    Given Expression A+A'B+A'C'

    Solution
    (A)(A'+B)(A'+C')




    Is this right? n If it is wrong plzz given me proper suggetion
     
    #1
  2. u5Al3

    u5Al3 New Member

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    Dec 24, 2010
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    i think
    A+A'B+A'C'
    = A'(A'+B)'(A'+C')'
    = A'(A.B')(A.C)
    = B'C
    =(B+C')
    = 1(B+C')
    = (A+A')(B+C')
     
    #2
  3. milee

    milee Member

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    Sep 20, 2007
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    i think the following might work

    A+A'B+A'C'
    A+A'(B+C')
    A+A'(B+1-C) //C+C'=1
    A+A'(1-C) //1+B=1
    A+A'C'
    (A+A')(A+C') //X+YZ=(X+Y)(X+Z)
    1(A+C')
    A+C'
     
    #3
  4. Georacer

    Georacer Moderator

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    Nov 25, 2009
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    #4
  5. CSharpque

    CSharpque Thread Starter Member

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    Sep 23, 2011
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    Plzz give me ans surely
     
    #5
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