My Basic Electronics text states: Current is the same amount in all the series components. It baffles me that matched resistances can render current and voltage to zero as in the Wheatstone Bridge. If one constructed a series-parallel circuit using four matched 100 watt light bulbs for the resistances in the same configuration as the Wheatstone Bridge, does that mean you could grab the bare wires and not be electrocuted? How can there be current in some parts of the circuit (enough to light up the bulbs) and yet zero current where the galvanometer is connected? What am I missing?