homework question #4

Discussion in 'Homework Help' started by cgeorge5150, Oct 8, 2009.

  1. cgeorge5150

    Thread Starter New Member

    Oct 8, 2009
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    determine the value of R2 and the total power dissipated by the load resistors.

    Since Voltage is the same in parallel, I used Ir3 x R3 and got voltage of 108V. Ir1= 108V/15K Ohm = 7.2mA. Itotal = 13.2mA. 13.2mA-2.3mA-7.9mA= 3.7mA. R2= 108V/3.7mA= 29k Ohm. Power is V(squared)/Rtotal. Rtotal= reciprocal of sum of resistors. Power equals 1.4 Watts
     
    Last edited: Oct 8, 2009
  2. blueroomelectronics

    AAC Fanatic!

    Jul 22, 2007
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    Do the work first then post your answer. We're not a homework service.
     
  3. cgeorge5150

    Thread Starter New Member

    Oct 8, 2009
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    blue room, wasn't asking for answer, was looking for guidance. So your ideaology that you are the enforcer of this website is not appreciated.
     
  4. blueroomelectronics

    AAC Fanatic!

    Jul 22, 2007
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    Guess you didn't read the sticky.
     
  5. hobbyist

    Distinguished Member

    Aug 10, 2008
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    That's the answer I came up with.

    Good job in figuring that out systematically.
    You seem to understand the basic theorems KVL and KCL and ohms law, quite well.
     
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