# homework question #4

Discussion in 'Homework Help' started by cgeorge5150, Oct 8, 2009.

1. ### cgeorge5150 Thread Starter New Member

Oct 8, 2009
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determine the value of R2 and the total power dissipated by the load resistors.

Since Voltage is the same in parallel, I used Ir3 x R3 and got voltage of 108V. Ir1= 108V/15K Ohm = 7.2mA. Itotal = 13.2mA. 13.2mA-2.3mA-7.9mA= 3.7mA. R2= 108V/3.7mA= 29k Ohm. Power is V(squared)/Rtotal. Rtotal= reciprocal of sum of resistors. Power equals 1.4 Watts

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2. ### blueroomelectronics AAC Fanatic!

Jul 22, 2007
1,758
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Do the work first then post your answer. We're not a homework service.

3. ### cgeorge5150 Thread Starter New Member

Oct 8, 2009
9
0
blue room, wasn't asking for answer, was looking for guidance. So your ideaology that you are the enforcer of this website is not appreciated.

4. ### blueroomelectronics AAC Fanatic!

Jul 22, 2007
1,758
98
Guess you didn't read the sticky.

5. ### hobbyist Distinguished Member

Aug 10, 2008
773
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That's the answer I came up with.

Good job in figuring that out systematically.
You seem to understand the basic theorems KVL and KCL and ohms law, quite well.