Homework Help. Thevenin Equivalent and more.

Discussion in 'Homework Help' started by jd53887, Mar 9, 2010.

  1. jd53887

    Thread Starter New Member

    Mar 9, 2010
    1. Can someone guide me as to how I can build a Thevenin Equivalent model for this problem?

    At the output of a DC circuit, it's 6 volts without any load attached. With a load of 1kΩ, the voltage becomes 4.

    I'm asked to find the ohm and voltage of the Thevenin Equivalent.


    I got the equivalent ohms by solving for Req = (Voc/Vab -1) *Rtest, which is 500ohms

    I don't want to sound stupid, but is the Thevenin Equivalent voltage 6v? seems too simple.
    Last edited: Mar 9, 2010
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    Your solution is fine. Vth=6V works. Too simple is better than too complicated!
    jd53887 likes this.
  3. jd53887

    Thread Starter New Member

    Mar 9, 2010
    problem 2:

    v(t) = Vm sin (2(pi) * f * t)

    Vm = x
    2(pi) * f = y

    waveform 1: v(t) = x sin (y * t)
    waveform 2: v(t) = x sin (y * t - z)

    I don't know how to solve this. I'm looking through my notes... and I could solve it without that z (just add the x together)... but I don't know what to do now. x is 20 and y is 3.14159265 and z is 1.5 if that matters.

    I'm looking for the peak value of their sum and phase shift of their sum in degrees

    EDIT: What if I put this in the graphing calculator and get the Peak value? y= (20sin(3.14y)) + (20sin(3.14y-1.5))
    which I got the answer of 29.26754852234942V

    would the phase shift be converting z (which is in radians) into degrees? 1.5*57.3 = 85.95
    Last edited: Mar 9, 2010
  4. MilK


    Mar 1, 2008
    peak value of sum = x + x

    -z is the phase shift for waveform 2. phase shift of their sum = 0 + z