hello again a sinusoidal current is specified by the expression, i=0.1 sin (200 pie t +pie/2) determine a.) the peak value of the current, b.) the frequency of the current, c.) the phase angel, and , d.) the instantaneous value of the current at t=5 milliseconds (use radian measure) for a i have i=0.1 sin(200 pie t + pie/2) i=0.1 sin(200 pie 0.005 + pie/2) i= 0.1 sin (3.142 +1.57) i=0.082 peak to peak ipeak=0.082/2 ipeak=0.041A b.) f= 1/t f=1/0.005 f=200 Hz could you tell me if i am correct thus far for c.) i have found the equation sin(t+pie/2)=cos(t) is that correct one to use, if so how do i impliment it? for d.) not sure what to do there - any help would be greatly appreciated cheers guys
For a sinusoidal waveform, i(t)=A*sin(omega*t+theta) where: A is your peak value omega is 2*pi*freq. t is time (5 msecs in your case). Just plug it in and solve. theta is the phase shift. You don't need trig identity sin(theta + pi/2)=cos(theta). Resolve your problem with this info.