high frequency amplifier

Thread Starter

king40

Joined Jul 17, 2013
75
Hi friends

I need circuit for frequency boost
My frequency betwean 40hz to 3khz
And i want boost this
Very boost :D
Thanks for any help
 

Thread Starter

king40

Joined Jul 17, 2013
75
Hi shteii
For example my vpp is 5v
And my frequency is 600hz
I want incerase my vpp to 12 or 9V whithout my frequency changed
Thanks
 

Ramussons

Joined May 3, 2013
1,404
Hi shteii
For example my vpp is 5v
And my frequency is 600hz
I want incerase my vpp to 12 or 9V whithout my frequency changed
Thanks
What is the waveform? What is the Voltage Swing / Range of this 5 Volt signal?

If it's Rectangular or Square 0 to 5 volts, just feed the 5V signal to a CMOS gate with a supply of 12 or 9 Volts.

Or simply a single NPN transistor and 2 Resistors if Inversion is not an issue.

Ramesh
 
Last edited:

Thread Starter

king40

Joined Jul 17, 2013
75
What is the waveform? What is the Voltage Swing / Range of this 5 Volt signal?

If it's Rectangular or Square 0 to 5 volts, just feed the 5V signal to a CMOS gate with a supply of 12 or 9 Volts.

Ramesh
thanks Ramesh

yes waveform is Square (Micro Square Wave) and 0 to 5 volt.
you have a circuit for your idea
thanks
 

Thread Starter

king40

Joined Jul 17, 2013
75
very thanks body
this is increase 5v p-p to 12v p-p?
and other question
if i want boost my frequency
how i can?:(
 

crutschow

Joined Mar 14, 2008
34,280
thanks
but i know little about analog
i need circuit or tutorial:(
The CD4504 is a digital circuit. You just connect 5V to power the input section (Vcc) and 9-12V to power the output section (Vdd). That will convert the 5V input signal to 9-12V at the output.
 

ian field

Joined Oct 27, 2012
6,536
thanks Ramesh

yes waveform is Square (Micro Square Wave) and 0 to 5 volt.
you have a circuit for your idea
thanks
If your signal source has decent current sink capability, you can use a cascade (common gate) MOSFET - that is the gate is connected to the 5V rail, the drain through RL to the 12V rail and the source driven directly by the output of your signal source - there is no current gain, so the source has to sink the same current as the load takes, but you get your 5V to 12V level translation.

If the signal source can't handle (sink) the load current, you'll have to drive a MOSFET that can - chances are any common MOSFET will handle the 12V for the load, but the signal will be inverted.
 

Thread Starter

king40

Joined Jul 17, 2013
75
many thanks of all.it works
now output vp-p is 12v
and
if i want to give boost to my frequency
now how i can???
 

bertus

Joined Apr 5, 2008
22,270
Hello,

The frequency is likely being generated using delay loops in the micro.
Changing the timing of the loops will change the frequency.

I have no experience with micros.

Bertus
 
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