Help with this integral

Discussion in 'Math' started by u-will-neva-no, May 16, 2011.

  1. u-will-neva-no

    Thread Starter Member

    Mar 22, 2011
    230
    2
    Hello :)

    Im having trouble with this integral, and im sure there is a way to do it quickly...anyway, here is the equation:

     \frac{1-y}{3}  e\frac{(1-y)^2}{2} dy

    I want to do the *trick* where you start with y = and then diffentiate and then just change the y = formula...but I cant remember how to do it...
     
  2. t_n_k

    AAC Fanatic!

    Mar 6, 2009
    5,448
    782
    make a substitution of a new variable such that ...

    v={(1-y)^2}/2
    dv=?? dy

    and so on ....
     
    u-will-neva-no likes this.
  3. galoisxss

    New Member

    Jun 26, 2011
    1
    0
    \frac{(1-y)}{3}e^{\frac{(1-y)^{2}}{2}}dy=-\frac{1}{3}∫e^{\frac{(1-y)^{2}}{2}}d(\frac{(1-y)^{2}}{2})

    make a substitution of a new variable such that ...

    v=\frac{(1-y)^{2}}{2}
    that will be
    -\frac{1}{3}∫e^{v}dv

    and so on ....
     
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