# Help with SERIES RLC CIRCUIT

Discussion in 'Homework Help' started by kwangwanhos, Oct 3, 2011.

1. ### kwangwanhos Thread Starter New Member

Oct 3, 2011
3
0
A simple series RLC circuit.

Source -------- Capacitor -------- Resistor -------- Inductor ----- back to source

E = 250V @ 0 degrees
X of capacitor is 63.3 ohms
X of inductor is 20 ohms

The voltage across the resistor is 125V at an angle of 60 degrees.

Find the voltage across the capacitor and inductor and determine the value of R.

Ok so I feel like i have this one on the tip of my tongue, but I keep getting the answer incorrect (answer in the back of book.) I tried doing a 2 equation-2 variable substitution, but it isn't working out. My voltage was actually pretty close (within .2 so I'm guessing it's because I use all of the digits in my TI-89), but my phase angle is way off.

2. ### milee Member

Sep 20, 2007
15
0
at first convert the capacitive and inductive resistance to a common reactance and then calculate it. u ll get the answer

3. ### Jess_88 Member

Apr 29, 2011
174
1
Maybe you could show your calculations? That way we can tell if its your calculator or your method.

Are you using
I = (E<theta)/(R + (jXL - jXC))