# Help with R, L, C series circuits

Discussion in 'Electronics Resources' started by kwangwanhos, Oct 3, 2011.

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1. ### kwangwanhos Thread Starter New Member

Oct 3, 2011
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An RLC circuit

Code ( (Unknown Language)):
1.
2. ----------------Capacitor-----------
3. |                                  |
4. |                                  |
5.
6.
7. E                              Resistor
8.
9.
10. |                                  |
11. |                                  |
12. --------------Inductor--------------
E = 250V @ 0 degrees
X of capacitor is 63.3 ohms
X of inductor is 20 ohms

The voltage across the resistor is 125V at an angle of 60 degrees.

Find the voltage across the capacitor and inductor and determine the value of R.

Ok so I feel like i have this one on the tip of my tongue, but I keep getting the answer incorrect (answer in the back of book.) I tried doing a 2 equation-2 variable substitution, but it isn't working out. My voltage was actually pretty close (within .2 so I'm guessing it's because I use all of the digits in my TI-89), but my phase angle is way off.

Last edited by a moderator: Oct 4, 2011
2. ### kwangwanhos Thread Starter New Member

Oct 3, 2011
3
0
So my picture didn't quite come out the way I planned it to, but all it is is an RLC circuit. Source with 250V at an angle of 0 degrees, then a capacitor with reactance of 63.3 ohms, then a resistor with 125V at angle of 60 degrees a crossed it, then an inductor with reactance 20 ohms goes back to source.

3. ### Georacer Moderator

Nov 25, 2009
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I have re-touched your circuit a bit to make it more readable, hope you don't mind.

4. ### t_n_k AAC Fanatic!

Mar 6, 2009
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Hi Georacer, OP 'kwangwanhos' also posted the same problem on the homework forum. Hopefully this will all get consolidated.

Hi kwangwanhos - it's confusing when you start more than one thread for the same problem.

5. ### Georacer Moderator

Nov 25, 2009
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